Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
For example,
Given the following matrix:
[
[ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ]
]
You should return [1,2,3,6,9,8,7,4,5].
http://www.programcreek.com/2013/01/leetcode-spiral-matrix-java/
public class Solution { public List<Integer> spiralOrder(int[][] matrix) { List<Integer> result = new ArrayList<Integer>(); if (matrix==null || matrix.length == 0 || matrix[0].length == 0) { return result; } int m = matrix.length; int n = matrix[0].length; int left = 0; int right=n - 1; int top = 0; int bottom = m - 1; while (result.size() < m * n) { for (int i = left; i <= right; i++) { result.add(matrix[top][i]); } top++; for (int i = top; i <= bottom; i++) { result.add(matrix[i][right]); } right--; // prevent duplicate row if (bottom < top) { break; } for (int i = right; i >= left; i--) { result.add(matrix[bottom][i]); } bottom--; // prevent duplicate column if (right < left) { break; } for (int i = bottom; i >= top; i--) { result.add(matrix[i][left]); } left++; } return result; } }
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